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Master gmat 2010 part 19

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In the question, you started with six terms. Let a through f equal those six terms: 19 5 a1b1c1d1e1f 6 114 5 a 1 b 1 c 1 d 1 e 1 f f 5 114 2 ~a 1 b 1 c 1 d 1 e! Letting f 5 the number removed, here’s the arithmetic-mean formula, applied to the remaining five numbers: 21 5 a1b1c1d1e 5 105 5 a 1 b 1 c 1 d 1 e Substitute 105 for (a 1 b 1 c 1 d 1 e) in the first equation: f 5 114 2 105 f59 Step 5:.