Đang chuẩn bị liên kết để tải về tài liệu:
Electric Machinery Fundamentals Power & Energy_4

Tham khảo tài liệu 'electric machinery fundamentals power & energy_4', kỹ thuật - công nghệ, điện - điện tử phục vụ nhu cầu học tập, nghiên cứu và làm việc hiệu quả | The per-unit impedance of the transmission line is Zh u jZ l 7.I0Q 0.00723 j0.0482 Zbase2 207.4 Q The per-unit impedance of Load 1 is Z Z .45 368 Q 1.513 j1.134 Zbase3 0.238 Q The per-unit impedance of Load 2 is ỵ- j0.8 Q -j3.36 load2 pu Zbase3 0.238 Q 7 The resulting per-unit per-phase equivalent circuit is shown below b With the switch opened the equivalent impedance of this circuit is ZEQ 0.010 j0.040 0.00723 j0.0482 0.040 j0.170 1.513 j1.134 ZEQ 1.5702 j1.3922 2.099Z41.6 The resulting current is 1Z0O . I A 0.4765Z - 41.6 2.099Z41.6 The load voltage under these conditions would be VLOad p I ZLoad 0.4765Z -41.6 1.513 j1.134 0.901Z -4.70 Vpoad V paV S 0.901 480 v 432 V The power supplied to the load is Load pa 12 R 0.4765 2 1.513 0.344 Load Load pa Sbase 0.344 1000 kVA 344 kW The power supplied by the generator is PG pu VI cos e 1 0.4765 cos41.6 0.356 Qg pu VI sin e 1 0.4765 sin41.6 0.316 Sg pu VI 1 0.4765 0.4765 Pg Pg puSbase 0.356 1000 kVA 356 kW Qg Qg puSbase 0.316 1000 kVA 316 kVAR Sg Sg pu Sbase 0.4765 1000 kVA 476.5 kVA The power factor of the generator is 61 PF cos 41.6 0.748 lagging c With the switch closed the equivalent impedance of this circuit is _ 1.513 1.134 - 3.36 7 0.010 0.040 0.00723 0.0482 0.040 0.170 t A EQ 1.513 1.134 - 3.36 ZEQ 0.010 0.040 0.00788 0.0525 0.040 0.170 2.358 0.109 ZEQ 2.415 0.367 2.443Z8.65 The resulting current is 1Z0 . I . .7 0.409z - 8.65 2.443Z8.65 The load voltage under these conditions would be VLoad pu I ZLoad 0.409Z -8.65 2.358 0.109 0.966Z -6.0 Voad Koa v s 0.966 480 V 464 V The power supplied to the two loads is the power supplied to the resistive component of the parallel combination of the two loads 2.358 pu. p p 12 Load 0.409 2 2.358 0.394 PLoad Poad pa Sbase 0.394 1000 kVA 394 kW The power supplied by the generator is Pg pu VI cos e 1 0.409 cos6.0 0.407 Qg pu VI sin e 1 0.409 sin 6.0 0.0428 i VI 1 0.409 0.409 Pg P . .pii Sbase 0.407 1000 kVA 407 kW Qg Qg.pu Sbase O.0428 1000 kVA 42.8 kVAR