tailieunhanh - Linear Agebra Prolem Book Part 11

Tham khảo tài liệu 'linear agebra prolem book part 11', kỹ thuật - công nghệ, cơ khí - chế tạo máy phục vụ nhu cầu học tập, nghiên cứu và làm việc hiệu quả | 286 LINEAR ALGEBRA PROBLEM BOOK These equations are easy to solve it turns out that the only solutions are the vector u 1 2 3 and its scalar multiples. Consequence the eigenvalue 3 of A has geometric multiplicity 1. For B the corresponding equations are a 3 3a -4a 5 3 3 3 6a 3 3 3y 37. The eigenspace of the eigenvalue 3 is 2-dimensional this time it is the set of all vectors of the form a 2a a . Consequence the eigenvalue 3 of B has geometric multiplicity 2. Partial conclusion A and B are not similar. The upper triangular form of both A and B must be something like 3 a 7 0 3 3. 0 0 3 Even a little experience with similarity indicates that that form is not uniquely determined the discussion of Problem 94 shows that similarity can effect radical changes in the stuff above the diagonal see in particular part b . Here is a pertinent special example that fairly illustrates the general case 1 -1 0 3 1 1 1 1 0 3 1 0 0 1 0 I 0 3 1 I 0 1 0 0 3 1 . 0 0 l 003 001 0 0 3 In view of these comments it is not unreasonable to restrict the search for triangular forms to those whose top right comer entry is 0. For A the search is for vectors u V and w such that Au 3u Av u 3v and Aw V 3w. As for u that s already at hand that s the eigenvector 1 2 3 found above. If V a Ị3 y the notation of the calculation that led to u is now abandoned then the equation for V says that a T 3 3a - -1 -a 2 3 y 3 3 2 3a 6 3 67 37 3. These equations are just as easy to solve as the ones that led to u. Their solutions are the vectors of the form a 2a 1 3a 3 a space of dimension 1. One of them one is enough is 0 1 3 call that one V. SOLUTIONS Chapter 7 287 If w a 3 7 another release of old notation then the equation for w becomes a 3 3a a 2 3 7 3 3 1 3a 6 3 67 37 3. The solutions of these equations are the vectors of the form a 2a 3a 1 a typical one of which with a 1 is w 1 2 4 . The vectors u V and w so obtained constitute the basis the matrix of A with respect to that basis is 3 1 0 0 3 11 0 0 3 as it .

TỪ KHÓA LIÊN QUAN
crossorigin="anonymous">
Đã phát hiện trình chặn quảng cáo AdBlock
Trang web này phụ thuộc vào doanh thu từ số lần hiển thị quảng cáo để tồn tại. Vui lòng tắt trình chặn quảng cáo của bạn hoặc tạm dừng tính năng chặn quảng cáo cho trang web này.