tailieunhanh - Báo cáo toán học: "A point in many triangles"

Tuyển tập các báo cáo nghiên cứu khoa học về toán học trên tạp chí toán học quốc tế đề tài: A point in many triangles. | A point in many triangles Boris Bukh Submitted Mar 3 2006 Accepted May 19 2006 Published May 29 2006 Mathematics Subject Classification 52C10 52C30 Abstract We give a simpler proof of the result of Boros and Furedi that for any finite set of points in the plane in general position there is a point lying in 2 9 of all the triangles determined by these points. Introduction Every set P of n points in Rd in general position determines Q J d-simplices. Let p be another point in Rd. Let C P p be the number of the simplices containing p. Boros and Ftiredi 2 constructed a set P of n points in R2 for which C P p 9 3 O n2 for every point p. They also proved that there is always a point p for which C P p 2 3 O n2 . Here we present a new simpler proof of the existence of such a point p. Proof Let P be a set of n points in the plane. By the extension of a theorem of Buck and Buck 3 due to Ceder 4 there are three concurrent lines that divide the plane into 6 parts each containing at least n 6 1 points in its interior. Denote by p the point of intersection of the three lines. Every choice of six points one from each of the six parts determines a hexagon containing the point p. Figure 1 a p 2 ABE or p 2 BCE b p 2 ACE and p 2 BDF Among the 3 20 triangles determined by the vertices of the hexagon at least 8 triangles contain the point p. Indeed from each of the six pairs of triangles situated as in THE ELECTRONIC JOURNAL OF COMBINATORICS 13 2006 N10 1 Figure 1a we get one triangle containing p. In addition p is contained in both triangles of the Figure 1b. Therefore by double counting the number of triangles containing p is at least 8 n 6 - 1 6 n 6 1 3 O n2 . 2 nA 9 w For the sake of completeness we include a sketch of a proof of the modification of the theorem of Buck and Buck that we used above. Proposition 1. Let p be a finite measure absolutely continuous with respect to the Lebesgue measure on R2. Then there are three concurrent lines that partition the plane into six parts of

TÀI LIỆU LIÊN QUAN
TỪ KHÓA LIÊN QUAN