tailieunhanh - Physics exercises_solution: Chapter 20

Bộ tài liệu bài tập tham khảo môn vật lý bậc đại học bằng tiếng anh Chapter 20 | a 2200J 4300J 6500J. b . oA onnn t . inn t oknn t kA 2600 J n 9qq qs qo a 9000 j 6400 j 2600 j . b 9000 j . aA 3700 _ n 99Q _ 99 no 2iO. 3 a 16100 0 0. b 16 100 J 3700 J 12 400 J. 16 100 J o c c C . . . 0. j -g. d 3700 J s 222 kW 298 hp. 20 4 a Q 1 Pt 180x1 3w 1-00 s 6 43 x 105 J a Q epl x 10 J. b Q Pt x 105 J 180 x 103 W x 105 J. a e - OMW 25 . b 1300MW 330MW 970MW. 1300 MW J Solving Eq. for r 1 y ln r ln 1 e or r 1 e 2 5 . If the first equation is used for instance using a calculator without the xy function note that the symbol e is the ideal efficiency not the base of natural logarithms. a Tb TarY 1 0 40 726K 453OC. b Pb ParY x 104 Pa Y x 106 Pa. a From Eq. e 1 r 1 040 58 . b 1 4 60 an increase of 2 . If more figures are kept for the efficiencies the difference is . 70 O- at Ind Qd J _ 1 9 1 M T a I W I k 2 10 x 10 J. b QH Qc W Qc 1 i x 104 J. P J - f V AT At KAt K yAt f 77 I 80kg x 105 J kg 485 J kg K K 128 W. 3600 s F 7 a 4 981 104 J 767W. b EER H P or EER s 3 413 1633W 413 27 105 J 60s - 104 J 60s f 767W a m Lf cIce AT cwJ ATWJ kg 334 x 103 J kg 2100 J kg K 4190 J kg K x 105 J. b JQc1 8-08x105 J 337 x 105J k 2 40 . c Qh QC x 105 J x 105 J x 106 J note that Qh IQcl 1 K . a Qh - Qc 550 J - 335 J 215 J. b Tc Th Qc Qh 620 K 335 J 550 J 378 K. c 1 - Qc Qh 1 - 335 J 550 J 39 . a From Eq. the rejected heat is i00K 6450 J x 103 J. 520 K b 103 J x 103 J. c From either Eq. or Eq. e . T T a Qh Qc T mL T Tc Tc 334x 103 J kg 107 J 1 or x 107 J to two figures b Qh I- Qc Qh I 1 - Tc Th x 107 J x 1 - 106 J. 20 16 a From Fci 20 13 320 K 415 J .