tailieunhanh - Lecture Electric circuits analysis - Lecture 20: Problems solving-Norton's theorem

Lecture Electric circuits analysis - Lecture 20: Problems solving-Norton's theorem. In this chapter, the following content will be discussed: Problems solving-Norton's theorem, maximum power transfer theorem. | Problems Solving-Norton's theorem Maximum Power Transfer Theorem Lecture 20 Using Norton's theorem, find the current through the load resistor RL. (Solved on 2 slides) RN = kΩ, RT = kΩ, IT= mA, I1=668 μA, IN=240 μA, IL=116 μA RN = kΩ, RT = kΩ, IT= mA, I1=668 μA, IN=240 μA, IL=116 μA Using Norton's theorem, find the voltage across R5 in the following Figure. (Solved on 3 slides) For 50 V: RT = R3 + R1 || R4 = kΩ, IT= mA, IN= mA, RN = kΩ, IR5= mA For 10mA: IN= mA, RN= kΩ, IR5= mA , IR5(tot)= , V5= V For 50 V: RT = R3 + R1 || R4 = kΩ, IT= mA, IN= mA, RN = kΩ, IR5= mA For 10mA: IN= mA, kΩ, IR5= mA , IR5(tot)= , V5= V For 50 V: RT = R3 + R1 || R4 = kΩ, IT= mA, IN= mA, RN = kΩ, IR5= mA For 10mA: IN= mA, kΩ, IR5= mA , IR5(tot)= , V5= V Reduce the circuit between terminals A and B in the following Figure to its Norton equivalent. (Solved on 2 slides) RN = kΩ, For VS: RT= kΩ, IT= 440 μA, IN1 = 156 μA down, For IS: IN2= mA down, IN = IN1 + IN2 = 156 μA + mA = mA RN = kΩ, For VS: RT= kΩ, IT= 440 μA, IN1 = 156 μA down, For IS: IN2= mA down, IN = IN1 + IN2 = 156 μA + mA = mA MAXIMUM POWER TRANSFER THEOREM The maximum power transfer theorem is important when you need to know the value of the load at which the most power is delivered from the source. For a given source voltage, maximum power is transferred from a source to a load when the load resistance is equal to the internal source resistance. Maximum power is transferred to the load when R L = R s The source in the following Figure has an internal source resistance of 75Ω. Determine the load power for each of the following values of load resistance: (a) 0 Ω (b) 25 Ω (c) 50 Ω (d) 75 Ω (e) 100 D (f) 125 Ω Draw a graph showing the load power versus the load resistance. (Solved on 2 slides) | Problems Solving-Norton's theorem Maximum Power Transfer Theorem Lecture 20 Using Norton's theorem, find the current through the load resistor RL. (Solved on 2 slides) RN = kΩ, RT = kΩ, IT= mA, I1=668 μA, IN=240 μA, IL=116 μA RN = kΩ, RT = kΩ, IT= mA, I1=668 μA, IN=240 μA, IL=116 μA Using Norton's theorem, find the voltage across R5 in the following Figure. (Solved on 3 slides) For 50 V: RT = R3 + R1 || R4 = kΩ, IT= mA, IN= mA, RN = kΩ, IR5= mA For 10mA: IN= mA, RN= kΩ, IR5= mA , IR5(tot)= , V5= V For 50 V: RT = R3 + R1 || R4 = kΩ, IT= mA, IN= mA, RN = kΩ, IR5= mA For 10mA: IN= mA, kΩ, IR5= mA , IR5(tot)= , V5= V For 50 V: RT = R3 + R1 || R4 = kΩ, IT= mA, IN= mA, RN = kΩ, IR5= mA For 10mA: IN= mA, kΩ, IR5= mA , IR5(tot)= , V5= V Reduce the circuit between terminals A and B in the following Figure to

• Điện - Điện tử
• Electric circuits analysis
• Lecture Electric circuits analysis
• Electrical engineering
• Parallel Circuits
• Series Circuits
• Circuit theorems
• Series parallel circuits