tailieunhanh - Lecture Engineering drawing and design - Lecture 20: Revision term 2

Lecture Engineering drawing and design - Lecture 20 introdution to revision term 2. The following will be discussed in this chapter: Let us revise, example shaft, solution, example bearings, example screws, load that a bolt can sustain. | Design web Design web To revise for 2nd test ME 1110 – Engineering Practice 1 Engineering Drawing and Design - Lecture 20 Test EME students: » 7th April 2015 @ 14,00 – B307 B/C Revision Term 2 Test MEA students: » 13th April 2015 @ 10,00 – Oakden Prof Ahmed Kovacevic Review test examples on Moodle Revise lectures 11-20 School of Engineering and Mathematical Sciences Room CG25, Phone: 8780, E-Mail: 1 Ahmed Kovacevic, City University London Let us REVISE Test example 2 Ahmed Kovacevic, City University London Design web Design web X X X X X X X X X X X X X X X X X X X X X X X X Design web Design web Design web Design web Design web Design web Design web Design web Example Shaft Determine the diameter for the solid round shaft 450 mm long, as shown in Figure. The shaft is supported by self-aligning bearings at the ends. Mounted upon the shaft are a V-belt pulley, which contributes a radial load of F1=8kN to the shaft, and a gear which contributes a radial load of F2=3kN. The two loads are in the same plane and have the same directions. The allowable bending stress (strength) is S=170 MPa. Assume factor of safety . F1=8 kN; a=450 mm c=200 mm S=170 Mpa d=? F2=3 kN b=150 mm Solution ∑M Assumptions - the weight of the shaft is neglected - the shaft is designed for the normal bending stress in the location of max. bending moment = − a R1 + (a − b) F1 + (a − b − c ) F2 R2 = 5 kN M max = M A = b ⋅ R1 = 900 Nm Second moment of area (moment of inertia) Section modulus =--------------------------------------------------------------πd4 d max span I= c= 64 2 3 I πd Z= = ≈ 3 c 32 f= SOLUTION: c R1 = 6 kN Stress = Strain = Bending moment / section modulus f =S σ Mc M 900 = f = = 170 ⋅106 I Z ⋅ d 3 ⋅ 900 d=3 = m = 20mm 170 ⋅105 S = fσ = f Design web Example bearings Example screws The cover of a pressurised cylinder is attached by .

• Cơ khí - Chế tạo máy
• Engineering drawing
• Engineering design
• Lecture Engineering drawing and design
• Engineering design
• Engineering design process
• Example shaft
• Communication modes
• Technical drawing standards
• Drawing procedure
• Assembly drawing
• Mechanical design process
• Problem definition
• Alternative solutions
• Satellite hinge
• Failure mode
• Textbook of engineering drawing
• Drawing instruments
• Dimensioning practices
• Geometrical constructions
• Orthographic projections
• The nature of design
• Communication of design
• Philosophy of designing
• Recognize types of pictorials
• Parallel projection
• Perspective projections
• Orthographic views
• Multiview drawings
• Section views
• Features geometric tolerances
• Geometric tolerances
• Surface finish
• Tolerance declaration
• Direct tolerancing method
• Tolerance terminology
• Editing commands
• Textual window
• Layer technique
• Multiline text
• Selecting objects
• Creating drawings
• Design communication
• Technical writing
• Graphical communication
• Mechanical design
• Preliminary design
• Mechanical systems
• Mechanical elements
• Rolling element bearings
• Bearing assembly
• Shaft design characteristics
• Shaft design
• Mechanical elements screws
• Non permanent joints
• Screw threads
• Space frames
• Space truss
• Gear types
• Gear parameters
• Effects analysis
• Oral presentation
• Isometric projection
• Freehand sketching
• Isometric views
• Engineering Drawing & CAD Standards
• Drawing Conventions
• Thread And Fastener Representation
• Line Conventions
• Drawing Media